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array(2) { [0]=> string(815) " select r.*, rc.info, t.title as threadtitle, u.username as username, u.anonymous as useranonymous, `f`.`value` AS `flairvalue`, `ft`.`name` AS `flairname`, `ft`.`colour` AS `flaircolour`, `ft`.`icon` AS `flairicon` from reply as r join thread as t on t.id = r.threadid join replycontent as rc on rc.replyid = r.id join user as u on u.id = r.userid left join `flair` `f` on `f`.`userid` = `u`.`id` and `f`.`categoryid` = `t`.`categoryid` left join `flairoption` `ft` on `ft`.`id` = `f`.`flairoptionid` where r.businessid = :businessId and r.threadid = :threadId group by r.id order by r.utcdated desc limit 0,50 " [1]=> array(2) { ["businessId"]=> int(1) ["threadId"]=> int(6009) } }

Years ago

Number of listeners??

Marketing companies do surveys. They approach a number of households and leave them with questionaires to fill out. Questions relating to the pattern of their radio listening would be part of the survey. As you tabulate numbers watching certain TV stations using the black box, the same method would be used to tabulate numbers listening to certain radio stations at certain times.

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Number of listeners??

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